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7 stages of bereavement - Imagemakers

📅 May 1, 2026 👤 scraface

May 01, 2026

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📌 eq 0\), we can divide both sides by \(\cos(z)\):

📌 2\sin(z) = 1 \quad \Rightarrow \quad \sin(z) = rac{1}{2}

📌 The solutions to \(\sin(z) = rac{1}{2}\) within the range \(0^\circ \leq z \leq 360^\circ\) are:

📌 z = 30^\circ, \quad z = 150^\circ

📌 Next, consider the case where \(\cos(z) = 0\):

📌 \cos(z) = 0 \quad \Rightarrow \quad z = 90^\circ, \quad z = 270^\circ

📌 We verify these solutions in the original equation:

📌 For \(z = 90^\circ\), \(\sin(180^\circ) = 0\) and \(\cos(90^\circ) = 0\), so it satisfies.

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