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x^2 + x - 2 = (x + 2)(x - 1).
R(x) = (x - 1)^2(x + 2).
The roots are $ x = 1 $ (with multiplicity 2) and $ x = -2 $. Therefore, there are **two distinct real roots**, but **three real roots counting multiplicity**. Since the question asks for the number of real roots (not distinct), the answer is:

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