Understanding the Quadratic Equation: t² + 5t + 6 = (t + 2)(t + 3)

When studying algebra, one of the most fundamental and widely used identities is the factorization of quadratic expressions. A classic example is transforming the quadratic equation t² + 5t + 6 = (t + 2)(t + 3). This identity not only simplifies solving quadratic equations but also deepens understanding of how polynomials factor, making it essential for students, teachers, and math enthusiasts alike.

Understanding the Context

What is t² + 5t + 6?

The expression t² + 5t + 6 is a quadratic trinomial consisting of three key components:

  • Quadratic term (t²)
  • Linear term (5t)
  • Constant term (6)

This expression appears in many real-world applications, from physics to economics, where relationships between variables are described by quadratics.

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2t-3=6sin(0.5t2)t2-t+2(2t-3)(t2-t+2)=6sin(0.5t2)solve | Chegg.com
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Solved Let S={1+t−t2,2t−t2+t3,−2+t2+t3,−3+t+t2+2t3} and W be | Chegg.com

Key Insights

Why Factor t² + 5t + 6?

Factoring the trinomial allows us to rewrite the expression as a product of two binomials:
(t + 2)(t + 3)
This factorization simplifies equation solving, graphing, and analysis. For example, setting (t + 2)(t + 3) = 0 lets us easily find the roots through the zero-product property.

How to Factor t² + 5t + 6?

To factor t² + 5t + 6, follow these steps:

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Final Thoughts

  1. Identify coefficients:
    We look for two numbers that multiply to 6 (the constant term) and add to 5 (the coefficient of t).

  2. Find suitable pair:
    The numbers 2 and 3 satisfy:

    • 2 × 3 = 6
    • 2 + 3 = 5

  3. Write the factorization:
    Groups the binomial expressions accordingly:
    t² + 5t + 6 = (t + 2)(t + 3)

This identity follows from the distributive law:
(t + 2)(t + 3) = t·t + t·3 + 2·t + 2·3 = t² + 5t + 6

Solving the Equation Using Factored Form

Consider the equation:
t² + 5t + 6 = 0

Using the factorization:
(t + 2)(t + 3) = 0

By the zero-product property, either:

  • t + 2 = 0 ⟹ t = -2
  • t + 3 = 0 ⟹ t = -3

Thus, the solutions are t = -2 and t = -3. These roots correspond to the x-intercepts of the parabola when viewed graphically.