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texas instruments ba ii plus professional advanced financial calculator - Imagemakers

📅 May 1, 2026 👤 scraface

May 01, 2026

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Since $\cos 60^\circ = \frac{1}{2}$, we have:
\cos\theta \cdot \frac{1}{2} = \cos\theta
\cos\theta = \sqrt{3}
But $\cos\theta = \sqrt{3}$ has no real solution since $|\cos\theta| \...
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = 2 \cos\theta \cos...
So the equation is $\cos\theta = \sqrt{3}$, which is impossible. Thus,...
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = 1
But given it's $\sqrt{3}$, and since maximum of $\cos\theta$ is 1, no...
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = 2 \cos\theta \cos...
So $\cos\theta = \sqrt{3}$ — still impossible. Hence, original equatio...

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