\( P(-800) = P_0 \cdot e^{(\ln 2 / 200)(-800)} = P_0 \cdot e^{-4\ln 2} = P_0 \cdot (e^{\ln 2})^{-4} = P_0 \cdot 2^{-4} = P_0 / 16 \)

Sun, 03 May 2026 11:49:49 +0000

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