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May 02, 2026

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x + y = \pm 10
Now compute \( x^2 - y^2 = (x - y)(x + y) \):
If \( x + y = 10 \), then \( x^2 - y^2 = 4 \cdot 10 = 40 \)
If \( x + y = -10 \), then \( x^2 - y^2 = 4 \cdot (-10) = -40 \)
But from \( x - y = 4 \) and \( x^2 + y^2 = 58 \), suppose \( x + y =...
Then solving \( x - y = 4 \), \( x + y = 10 \), add: \( 2x = 14 \Right...
Check: \( x^2 + y^2 = 49 + 9 = 58 \) â
Then \( x^2 - y^2 = 49 - 9 = 40 \)
If \( x + y = -10 \), then \( x = 2 \), \( y = -8 \), check \( x - y =...
e 4 \) â

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