Since $ |a| = |b| = 1 $, $ a \overline{a} = 1 $ and $ b \overline{b} = 1 $. However, observe that $ a^2 - b^2 = (a - b)(a + b) $, but no simplification arises directly. Instead, compute $ S + \overline{S} $:

Sat, 02 May 2026 10:54:33 +0000

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