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📅 May 1, 2026 👤 scraface

May 01, 2026

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\gcd(2^a - 1, 2^b - 1) = 2^{\gcd(a,b)} - 1
Here, $ a = 12 $, $ b = 18 $, so $ \gcd(12, 18) = 6 $.
Thus,
\gcd(2^{12} - 1, 2^{18} - 1) = 2^6 - 1 = 64 - 1 = 63
Therefore, the greatest common divisor is $ \boxed{63} $.
Question: What is the largest integer that must divide the product of...
Solution: Let the four consecutive integers be $ n, n+1, n+2, n+3 $.
Among any four consecutive integers:
There are at least two even numbers, and one of them is divisible by 4...
There is exactly one multiple of 4 and another even, so $ 8 \mid $ pro...

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